Integrand size = 25, antiderivative size = 111 \[ \int \frac {\sin ^2(e+f x)}{\sqrt {a+b \sin ^2(e+f x)}} \, dx=\frac {E\left (e+f x\left |-\frac {b}{a}\right .\right ) \sqrt {a+b \sin ^2(e+f x)}}{b f \sqrt {1+\frac {b \sin ^2(e+f x)}{a}}}-\frac {a \operatorname {EllipticF}\left (e+f x,-\frac {b}{a}\right ) \sqrt {1+\frac {b \sin ^2(e+f x)}{a}}}{b f \sqrt {a+b \sin ^2(e+f x)}} \]
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Time = 0.09 (sec) , antiderivative size = 111, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {3251, 3257, 3256, 3262, 3261} \[ \int \frac {\sin ^2(e+f x)}{\sqrt {a+b \sin ^2(e+f x)}} \, dx=\frac {\sqrt {a+b \sin ^2(e+f x)} E\left (e+f x\left |-\frac {b}{a}\right .\right )}{b f \sqrt {\frac {b \sin ^2(e+f x)}{a}+1}}-\frac {a \sqrt {\frac {b \sin ^2(e+f x)}{a}+1} \operatorname {EllipticF}\left (e+f x,-\frac {b}{a}\right )}{b f \sqrt {a+b \sin ^2(e+f x)}} \]
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Rule 3251
Rule 3256
Rule 3257
Rule 3261
Rule 3262
Rubi steps \begin{align*} \text {integral}& = \frac {\int \sqrt {a+b \sin ^2(e+f x)} \, dx}{b}-\frac {a \int \frac {1}{\sqrt {a+b \sin ^2(e+f x)}} \, dx}{b} \\ & = \frac {\sqrt {a+b \sin ^2(e+f x)} \int \sqrt {1+\frac {b \sin ^2(e+f x)}{a}} \, dx}{b \sqrt {1+\frac {b \sin ^2(e+f x)}{a}}}-\frac {\left (a \sqrt {1+\frac {b \sin ^2(e+f x)}{a}}\right ) \int \frac {1}{\sqrt {1+\frac {b \sin ^2(e+f x)}{a}}} \, dx}{b \sqrt {a+b \sin ^2(e+f x)}} \\ & = \frac {E\left (e+f x\left |-\frac {b}{a}\right .\right ) \sqrt {a+b \sin ^2(e+f x)}}{b f \sqrt {1+\frac {b \sin ^2(e+f x)}{a}}}-\frac {a \operatorname {EllipticF}\left (e+f x,-\frac {b}{a}\right ) \sqrt {1+\frac {b \sin ^2(e+f x)}{a}}}{b f \sqrt {a+b \sin ^2(e+f x)}} \\ \end{align*}
Time = 0.27 (sec) , antiderivative size = 78, normalized size of antiderivative = 0.70 \[ \int \frac {\sin ^2(e+f x)}{\sqrt {a+b \sin ^2(e+f x)}} \, dx=\frac {\sqrt {2 a+b-b \cos (2 (e+f x))} \left (E\left (e+f x\left |-\frac {b}{a}\right .\right )-\operatorname {EllipticF}\left (e+f x,-\frac {b}{a}\right )\right )}{b f \sqrt {\frac {2 a+b-b \cos (2 (e+f x))}{a}}} \]
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Time = 1.05 (sec) , antiderivative size = 93, normalized size of antiderivative = 0.84
method | result | size |
default | \(-\frac {a \sqrt {\frac {\cos \left (2 f x +2 e \right )}{2}+\frac {1}{2}}\, \sqrt {\frac {a +b \left (\sin ^{2}\left (f x +e \right )\right )}{a}}\, \left (F\left (\sin \left (f x +e \right ), \sqrt {-\frac {b}{a}}\right )-E\left (\sin \left (f x +e \right ), \sqrt {-\frac {b}{a}}\right )\right )}{b \cos \left (f x +e \right ) \sqrt {a +b \left (\sin ^{2}\left (f x +e \right )\right )}\, f}\) | \(93\) |
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\[ \int \frac {\sin ^2(e+f x)}{\sqrt {a+b \sin ^2(e+f x)}} \, dx=\int { \frac {\sin \left (f x + e\right )^{2}}{\sqrt {b \sin \left (f x + e\right )^{2} + a}} \,d x } \]
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\[ \int \frac {\sin ^2(e+f x)}{\sqrt {a+b \sin ^2(e+f x)}} \, dx=\int \frac {\sin ^{2}{\left (e + f x \right )}}{\sqrt {a + b \sin ^{2}{\left (e + f x \right )}}}\, dx \]
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\[ \int \frac {\sin ^2(e+f x)}{\sqrt {a+b \sin ^2(e+f x)}} \, dx=\int { \frac {\sin \left (f x + e\right )^{2}}{\sqrt {b \sin \left (f x + e\right )^{2} + a}} \,d x } \]
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\[ \int \frac {\sin ^2(e+f x)}{\sqrt {a+b \sin ^2(e+f x)}} \, dx=\int { \frac {\sin \left (f x + e\right )^{2}}{\sqrt {b \sin \left (f x + e\right )^{2} + a}} \,d x } \]
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Timed out. \[ \int \frac {\sin ^2(e+f x)}{\sqrt {a+b \sin ^2(e+f x)}} \, dx=\int \frac {{\sin \left (e+f\,x\right )}^2}{\sqrt {b\,{\sin \left (e+f\,x\right )}^2+a}} \,d x \]
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